Where is collision happening in this question? How to solve it?A cart of mass 50 kg is moving on a straight track with a speed of 12 metre per second a mass of 10 kg is gently put into the card what will be the velocity of the cart after this

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Solution

Mass of cart , M = 50 kg and speed of cart, V = 12m/s
Let mass m=10 kg put into cart with speed v
According to law of conservation of momentum (newton's second law)

MV=mv
50 x 12 = (50+10) x v
v = 10 m/s

now velocity of cart after put 10 kg is 10 m/s

i hope it will help you
regards

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Where is collision happening in this question? How to solve it?A cart of mass 50 kg is moving on a straight track with a speed of 12 metre per second a mass of 10 kg is gently put into the card what will be the velocity of the cart after this

Mass of cart , M = 50 kg and speed of cart, V = 12m/s Let mass m=10 kg put into cart with speed v According to law of conservation of momentum (newton's second law) MV=mv 50 x 12 = (50+10) x v v = 10 m/s now velocity of cart after put 10 kg is 10 m/s i hope it will help you regards

Mass of cart , M = 50 kg and speed of cart, V = 12m/s
Let mass m=10 kg put into cart with speed v
According to law of conservation of momentum (newton's second law)

MV=mv
50 x 12 = (50+10) x v
v = 10 m/s

now velocity of cart after put 10 kg is 10 m/s

i hope it will help you
regards