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Where must an...

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Where must an 800N object be hung on a uniform rod of weight 100 N so that a girl at one end supports 1/3rd of the weight as compared to that supported by a woman at the other end?

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Solution

$l e t t h e l e n g t h o f t h e r o d b e L b a l a n c e t h e t o r q u e \frac{800}{3} (\frac{L}{2}) = 800 x x = \frac{L}{6} t h e w e i g h t s h o u l d b e h u n g a t L / 6 f r o m t h e c e n t e r t o t h e o t h e r s i d e w h e r e g i r p o s i t i o n e d . R e g a r d s$

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