Whether 6 power n can end with the digit 0 for any natural number n

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Solution

$6^{1} = 6 6^{2} = 36 6^{3} = 216 6^{4} = 1296$
Hence, you can see that whatever be the power of 6, it will end in 6 only.

Only, $6^{0} = 1$ .

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