Question

Whether $8$power $n$ ,where $n$ is a natural number, can end with zero?

Answer 1

Explanation.

A number ends with zero if it is multiplied by $5$ or $10$ or by the multiples of $10$ .

So, here the number $8$ has factors $1,2,4$ and $8$.

It does not contain $5$ and $10$ as prime factors.

And, In the prime factorization of $8n=\left(2\times 4\right)n$

Here, It doesn’t have $5$ in its prime factorization

Therefore, $8^n$cannot end with the digit $0$