Question

Which among the following are isoelectronic $N{O}_3^{-},C{O}_3^{2-},Cl{O}_3^{-},S{O}_2$

• A. NO₃^-, CO₃^2-, ClO₃^-
• B. NO₃^-, CO₃^2-, SO₂
• C. CO₃^2-, ClO₃^-, SO₂
• D. None of these

Answer 1

The correct option is B

NO₃^-, CO₃^2-, SO₂

No. Of electrons in $N{O}_3^{-}$ = $7+(8\times 3)+1=32$

No. Of electrons in $C{O}_3^{-2}=6+(8\times 3)+2=32$

No. Of electrons in $S{O}_2=16+(8\times 2)=32$