The correct option is D (−3,9)
Given, linear equation
5x+2y=3
Putting the value of x and solving for y we get,
option(a)––––––––––: putting x=1 in the equation we get,
5×1+2y=3
⇒2y=3−5
⇒2y=−2⇒y=−1
but given ordered pair in option(a) is (1,1). So, (1,1) is not the ordered pair satisfying this equation.
option(b)––––––––––:putting x=−1 we get,
5×(−1)+2y=3
⇒2y=3+5⇒2y=8⇒y=4
This ordered pair (−1,4) satisfy the linear equation in two variable.
option(c)––––––––––: Putting x=5 we get,
5×(5)+2y=3
⇒2y=3−25⇒2y=−22⇒y=−11
This ordered pair (5,−11) satisfy the linear equation in two variable.
option(d)––––––––––: Putting x=−3 we get,
5×(−3)+2y=3
⇒2y=3+15
⇒2y=18⇒y=9
This ordered pair (−3,9) satisfy the linear equation in two variable.