Which among the following cannot exist in an aqueous solution?

{N H}_{4}^{+}

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{N O}_{3}^{-}

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{N O}_{2}^{-}

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{N H}_{2}^{-}

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Solution

The correct option is C ${N H}_{2}^{-}$
Amide $N H_{2}^{-}$ is a stronger base than $O H^{-}$ because the -ve charge in $N H 2^{-}$ is more localized, it is spread over two lp. In $O H^{-}$ , the charge is spread over three lp. So the equilibrium.
lies completely to the right leading to the formation of ammonia gas. So it does not form the aqueous solution.
$N H 2^{-} + H_{2} O \to N H_{3} + O H^{-}$ .
Hence option D is correct.

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