Question

Which among the following contains same number of molecules as in $22grams$ of $N_{2}O$?

• A. $60g$ of $C_2{H}_6$
• B. $24g$ of $C{H}_4$
• C. $20g$ of $HN{O}_3$
• D. $14g$ of $N_2$

Answer 1

The correct option is D $14g$ of $N_2$

Moles of $N_{2}O=\frac{22}{44}=0.5$ moles

$\therefore$ Molecules of $N_{2}O=0.5\times N_A$

For (A), Molecules of $C_2{H}_6=\frac{60}{30}\times N_A=2N_A$

For (B), Molecules of $C{H}_4=\frac{24}{16}\times 1.5N_A$

For (C), Molecules of $HN{O}_3=\frac{20}{63}\times N_A=0.317N_A$

For (D), Molecules of $N_2=\frac{14}{28}\times N_A=0.5\times N_A$

From the above calculations, it is clear that

No. of molecules in $22$ grams of $N_{2}O$= No. of molecules in $14$ gram of $N_2$

Therefore, $14g$ $of$ $N_2$ is the correct answer.