Question

Which among the following has maximum number of atoms?

Answer 1

Mole of $N_2=\frac{14}{28}=0.5$
Mole of atoms of $N_2=0.5\times 2=1$
Mole of $C{H}_4=\frac{8}{16}=0.5$
Mole of atoms of $C{H}_4=0.5\times 5=2.5$
Mole of $C{O}_2=\frac{22}{44}=0.5$
Mole of atoms of $C{O}_2=0.5\times 3=1.5$
Mole $C_2{H}_6=\frac{15}{30}=0.5$
Mole of atoms of $C_2{H}_6=0.5\times 8=4$