Question

Which among the following is a bi-dentate ligand ?

• A. $C{H}_{3}CO{O}^{-}$
• B. $:OC{N}^{-}$
• C. $:NC{O}^{-}$
• D. $C{H}_3-\underset{\underset{\cdot \cdot }{:O}}{\underset{\parallel }{C}}-CH=\underset{\underset{\cdot \cdot }{:O:}}{\underset{\parallel }{C}}-C{H}_3$

Answer 1

Answer: (D)

$C{H}_3-\underset{\underset{\cdot \cdot }{:O}}{\underset{\parallel }{C}}-CH=\underset{\underset{\cdot \cdot }{:O:}}{\underset{\parallel }{C}}-C{H}_3$

Bidentate ligands are Lewis bases that donate two pairs ("bi") of electrons to a metal atom. Bidentate ligands are often referred to as chelating ligands ("chelate" is derived from the Greek word for "claw") because they can "grab" a metal atom in two places.

$C{H}_3-\underset{\underset{\cdot \cdot }{:O}}{\underset{\parallel }{C}}-CH=\underset{\underset{\cdot \cdot }{:O:}}{\underset{\parallel }{C}}-C{H}_3$ is bi-dentate ligand because it grabs the metal at 2 positions(at oxygen atoms)

Hence option D is correct.