Which among the following is a prime triplet?

{3, 5, 7}

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{17, 19, 23}

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{41, 43, 47}

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{67, 71, 73}

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Solution

The correct option is A
{3, 5, 7}

The set of three consecutive prime numbers with a difference of 2 is called the prime triplet. Therefore, {3, 5, 7} is a prime triplet.

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Similar questions

4 \frac{3}{5} \times 2 \frac{3}{7} = \frac{23}{5} \times \frac{17}{7} = ?

\frac{5}{∠ 3} + \frac{19}{∠ 5} + \frac{41}{∠ 7} + \frac{71}{∠ 9} + \dots \dots

1^{3} = 1

2^{3} = 3 + 5

3^{3} = 7 + 9 + 11

4^{3} = 13 + 15 + 17 + 19

n^{3}

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