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Question

Which among the following is/are odd functions?

A
f(x)=x(ex1ex+1)
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B
g(x)=ax1ax+1
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C
h(x)=log(x6+x2+1)
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D
k(x)=x(x2|x|)
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Solution

The correct option is D k(x)=x(x2|x|)
Clearly h(x)=log(x6+x2+1) is an even function because it has even powers of x

For f(x)=x(ex1ex+1)
f(x)=x(ex1ex+1)=x(1exex+1)=f(x)
f(x) is even function.

For g(x)=ax1ax+1
g(x)=ax1ax+1g(x)=1ax1+axg(x)=g(x)
g(x) is odd function.

For k(x)=x(x2|x|)
k(x)=x(x2|x|)k(x)=k(x)
k(x) is odd function.

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