Which among the following is correct, where I = current, V = Potential difference, R = Resistance and P = electric power?

P = I^{v}

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P = \frac{V^{2}}{R}

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V = P^{2} I

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V I = P^{2}

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Solution

The correct option is B $P = \frac{V^{2}}{R}$
Electric power = Work done/ unit time.
Now W = qV
Hence, $P = \frac{q V}{t} = V I$
Now, from Ohm's law, we know that $V = I R, s o I = \frac{V}{R}$
Hence, $P = V \times \frac{V}{R} = \frac{V^{2}}{R}$

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