Which among the following is not a disproportionation reaction i?

3 H_{3} {P O}_{3} \to 2 H_{3} {P O}_{2} + {P H}_{3}

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2 H C H O {O H}^{-} - -- \to H C O ¯ ¯¯ ¯ O + {C H}_{3} O H

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4 P + 3 N a O H + 3 H_{2} O \to {P H}_{3} + 3 {N a H}_{2} {P O}_{2}

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{N H}_{4} {N O}_{3} \to N_{2} O + 2 H_{2} O

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Solution

The correct option is A $3 H_{3} {P O}_{3} \to 2 H_{3} {P O}_{2} + {P H}_{3}$
Among the following reactions
${N H}_{4} {N O}_{3} ⟶ N_{2} O + 2 H_{2} O$ is not a dispropotionation reaction.
It is a double decomposition reaction disproportional reaction :-
A reaction in which the reactants are simultaneously oxidised and reduced are known as disproportional reaction.
In the above reaction ${N H}_{4} {N O}_{3}$ is oxidised but not reduced and hydrogen is also oxidised. So, this reaction is not a disproportional reaction.

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{4 P + 3 K O H + 3 H}_{2} O ⟶ {3 K H}_{2} {P O}_{2} + {P H}_{3}

P_{4} + 3 N a O H + 3 H_{2} O Δ - \to 3 N a H_{2} {P O}_{2} + {P H}_{3}

{N H}_{4}^{+} + {N O}_{3}^{-} ⟶ N_{2} O + 2 H_{2} O

P_{4} + 3 N a O H + 3 H_{2} O \to 3 N a H_{2} P O_{2} + P H_{3}

P_{4} + 3 N a O H + 3 H_{2} O △ ⟶ P H_{3} + 3 N a H_{2} P O_{2}

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