Which among the following is not obtained when ethyl chloride and n-propyl chloride undergoes Wurtz reaction?

n–butane

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n–pentane

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n–hexane

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isobutane

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Solution

The correct option is D isobutane
Wurtz reaction between ethyl chloride and n-propyl chloride
$2 C H_{3} C H_{2} - C l + 2 N a D r y e t h e r - ------ \to C H_{3} C H_{2} C H_{2} C H_{3} (n - b u t a n e) + 2 N a C l$
$C H_{3} C H_{2} - C l + C H_{3} C H_{2} C H_{2} - C l + 2 N a D r y e t h e r - ------ \to C H_{3} C H_{2} C H_{2} C H_{2} C H_{3} (n - p e n t a n e) + 2 N a C l$
$2 C H_{3} C H_{2} C H_{2} - C l + 2 N a D r y e t h e r - ------ \to C H_{3} C H_{2} C H_{2} C H_{2} C H_{2} C H_{3} (n - h e x a n e) + 2 N a C l$
But ${(C H_{3})}_{2} C H C H_{3} (i s o b u t a n e)$ is not possible to prepare using ethyl chloride and propyl chloride.

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