Question

Which among the following operations would increase the capacity of a parallel plate capacitor initially filled with air?

​​​​​​​$[$0.77 Mark$]$

• A. Inserting a dielectric slab between the plates of the capacitor
• B. Increasing the distance between the plates of the capacitor
• C. Decreasing the distance between the plates of the capacitor
• D. Both options (A) and (C)

Answer 1

The correct option is D Both options (A) and (C)

Capacitance of the parallel plate capacitor(filled with air) is given by
$C=\frac{{\epsilon }_{0}A}{d}$

Where,
${\epsilon }_0$ - Permittivity of free space
$A$ - Area of the plates of the capacitor
$d$ - Distance between the plates of the capacitor (Plate separation)

Whereas, Capacitance of the parallel plate capacitor (filled with dielectric medium) is given by
$C=\frac{K{\epsilon }_{0}A}{d}$

Where, $K$ is the dielectric constant

$C$ increases on inserting dielectric slab between the plates of the capacitor and decreasing plate separation.