Which among the following oxides can yield Nitric acid on hydrolysis?

N_{2} O_{3}

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N_{2} O_{4}

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N_{2} O_{5}

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N O_{2}

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Solution

The correct option is D $N O_{2}$
One of the more obvious options is $N_{2} O_{5}$ which is the anhydride of $H N O_{3}$ . In fact $N_{2} O_{5}$ is prepared by dehydrating $H N O_{3}$ using $P_{4} O_{10}$ .
$N_{2} O_{3} + H_{2} O \to 2 H N O_{2}$
Can you recall the steps involved in the Oswald process?
Ostwald process: Ammonia is converted to nitric acid in presence of a Catalyst such as platinum with $10 %$ Rhodium.
$4 N H_{3} (g) + 5 O_{2} (g) P t - --- \to 10 % R h 4 N O (g) + 6 H_{2} O (g)$
$2 N O + O_{2} \to 2 N O_{2}$
$3 N O_{2} + H_{2} O \to 2 H N O_{3} + N O$
Clearly, option D is also correct. What can you comment about $N_{2} O_{4}$ as a prospective answer here?
Yes! $N_{2} O_{4}$ is the low-temperature dimer of Nitrogen dioxide. So option B is also accurate.
But wait! We were talking about hydrolysis weren’t we?
$2 N O_{2} + H_{2} O \to H N O_{3} + H N O_{2}$

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