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Question

Which among the following pair(s) of function are identical.

A
f(x)=secxcosxtanxcotx,g(x)=cosxsecx+sinx cosecx
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B
f(x)=sgn(x26x+10),g(x)=sgn(cos2x+sin2(x+π3)) where sgn denotes signum function.
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C
f(x)=eln(x25x+6),g(x)=x25x+6
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D
f(x)=sinxsecx+cosx cosecx,g(x)=2cos2xcotx
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Solution

The correct option is B f(x)=sgn(x26x+10),g(x)=sgn(cos2x+sin2(x+π3)) where sgn denotes signum function.
Functions f(x) and g(x) are said to be equal or identical function's if
(i) Domain of f(x)=g(x) and
(ii) Range of f(x)=g(x)

For f(x)=secxcosxtanxcotx,g(x)=cosxsecx+sinxcosec x
Domain of both functions is xR{nπ2,nZ}
Also, both functions simplify to 1 i.e. Range ={1}
Hence, both functions are identical.

For f(x)=sgn(x26x+10),g(x)=sgn(cos2x+sin2(x+π3))
As x26x+10=(x3)2+1>0,cos2x+sin2(x+π3)>0
Hence f(x)=g(x)=1 xR. and Domain of f(x)=g(x)=R
Hence both functions are identical.

For f(x)=eln(x25x+6),g(x)=x25x+6
Domain of f(x) is x(,2)(3,) but domain of g(x)=R
Hence, they are not identical functions.

For
f(x)=sinxsecx+cosxcosec x,g(x)=2cos2xcotx
f(x)=sinxsecx+cosxcosec x
=2sinxcosx
=2cos2xcotx
=g(x)
And domain of both the functions is also same.
Hence, they are identical functions.

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