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Question

Which among the following term's in the expansion of (3ab+b3a)21will have the same power's for a and b.

A
8th term
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B
9th term
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C
10th term
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D
11th term
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Solution

The correct option is C 10th term
Let (r+1)th term has same power of a and b
Tr+1= 21Cr(3ab)21r(b3a)r
Exponent of a in the given expansion =21r3r6
Exponent of b in the given expansion =r221r6
The exponents of a and b are the same, therefore,
21r3r6=r221r6
On solving above equation, we get,
r=9
10th term has the same power of a and b.

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