Which among the following will be named as dibromidobis (ethylenediamine) chromium(III) bromide?

[C r (e n)_{3}] B r_{3}

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[C r (e n)_{2} B r_{2}] B r

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C r (e n) B r_{4}]^{-}

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[C r (e n) B r_{2}] B r

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Solution

The correct option is B $[C r (e n)_{2} B r_{2}] B r$
(a) We first name cation and then anion.
(b) If cation is complex, then we first name ligand in alphabetical order and then central atom with oxidation state remain numeral in common brackets.

$[C r (e n)_{2} B r_{2}] B r -$ is named as dibromidobis (ethylenediamine) chromium(III) bromide :

Ligands are : $B r$ (two), ethyenediammine (two).

Central ion : $C r (I I I)$ or $C r^{3 +}$

Counter ion : $B r^{-}$

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Similar questions

In IUPAC name of the following compound,the prefix bacause of -Br and suffix bacause of C = 0 will be respectively

C s B r_{3}

C s B r_{3}

{B r O_{3}}^{-} (a q .) + 5 {B r}^{-} (a q .) + 6 H^{+} (a q .) ⟶ 3 {B r}_{2} (l) + 3 H_{2} O (l)

({B r}_{2})

Which of the following statement is correct for $C s B r_{3}$ ?

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