The correct option is B (−2)−5×(−9)−7
(−2)−5×(−9)−7
=[(−1)×2]−5×[(−1)×9]−7
=[(−1)−5×2−5]×[(−1)−7×9−7]
(∵(a×b)n=an×bn)
=(−1)−5×(−1)−7×2−5×9−7
=(−1)−5+(−7)×2−5×9−7
=(−1)−12×2−5×9−7
=1(−1)12×25×97 (∵a−n=1an)
=11×25×97 [∵(−1)12=1]
=125×97>0
Hence, option (b.) is the correct one.