Question

Which angle is equal to $8$ times its complement?

Answer 1

It is given that the angle is $8$ times its complement.

Consider $x$ and $8x$ as the angles.

We know that, if two angles are complementary, then their sum is ${90}^o$.

Then, $x+8x={90}^0$

$⟹$ $9x={90}^0$

$⟹$ $x=\frac{90}{9}={10}^0$.

Here, the angles will be $x={10}^0$ and $8x=8\times {10}^o={80}^0$.