Question

Which bond is more polar in the following pairs of molecules?
a.) $H_{3}C-H,H_{3}C-Br$
b.) $H_{3}C-N{H}_2,H_{3}C-OH$
c.) $H_{3}C-OH,H_{3}C-SH$

• A. a. $H_{3}C-H$
  b. $H_{3}C-OH$
  c. $H_{3}C-OH$
• B. a. $H_{3}C-Br$
  b. $H_{3}C-OH$
  c. $H_{3}C-OH$
• C. a. $H_{3}C-H$
  b. $H_{3}C-N{H}_2$
  c. $H_{3}C-OH$
• D. a. $H_{3}C-H$
  b. $H_{3}C-N{H}_2$
  c. $H_{3}C-SH$

Answer 1

The correct option is B a. $H_{3}C-Br$

b. $H_{3}C-OH$
c. $H_{3}C-OH$
Among $H_{3}C-H$ and $H_{3}C-Br$, the $H_{3}C-Br$ bond is more ploar since $Br$ is more electronegative$\left(EN\right)$ than $H$.
Among $H_{3}C-N{H}_2$ and $H_{3}C-OH$, the $H_{3}C-OH$ bond is more ploar since $O$ is more electronegative$\left(EN\right)$ than $N$.
Among $H_{3}C-OH$ and $H_{3}C-SH$, the $H_{3}C-OH$ bond is more ploar since $O$ is more electronegative$\left(EN\right)$ than $S$.