Which cation has smallest radius

K^{+}

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N a^{+}

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L i^{+}

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B e^{2 +}

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Solution

The correct option is D $B e^{2 +}$
Li and Be belongs to second period while Na belongs to third and K potassium belongs to fourth period. So Li and Be are smaller in size.
Among $L i^{+}$ and $B e^{2 +}$ ; $B e^{2 +}$ is smaller in size due to high effective nuclear charge.

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Similar questions

Q. The set representing the correct order of ionic radius is:(A) Li+ > Be2+ > Na+ > Mg2+ (B) Na+ > Li+ > Mg2+> Be2+ (C) Mg2+ > Be2+ > Li+ > Na+ (D)Li+ > Na+ > Mg2+>Be2+(explain briefly)

Which cation has smallest radius

Which of the following cations has the smallest radius?

Q. Which ranks the following atoms

(L i, N a, K, R b)

from the smallest to largest atomic radius?

The charge/ size ratio of a cation determines its polarizing power. Which one of the following sequences represents the increasing order of the polarizing power of the cationic species, $K^{+}, C a^{2 +}, M g^{2 +}, B e^{2 +}$

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Which cation has smallest radius

The correct option is D Be2+Li and Be belongs to second period while Na belongs to third and K potassium belongs to fourth period. So Li and Be are smaller in size.Among Li+ and Be2+; Be2+ is smaller in size due to high effective nuclear charge.

The correct option is D $B e^{2 +}$
Li and Be belongs to second period while Na belongs to third and K potassium belongs to fourth period. So Li and Be are smaller in size.
Among $L i^{+}$ and $B e^{2 +}$ ; $B e^{2 +}$ is smaller in size due to high effective nuclear charge.