Which change for the $N_{2}$ molecule would give a bond order of 2.5?

+ 1

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Solution

The correct options are
A $+ 1$
C $- 1$
(A) $N_{2} = \frac{10 - 4}{2} = 3.0 \Rightarrow N_{2}^{+} = \frac{9 - 4}{2} = 2.5$
(C) $N_{2} = \frac{10 - 4}{2} = 3.0 \Rightarrow N_{2}^{-} = \frac{10 - 5}{2} = 2.5$

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