Which compound among the following has the lowest oxidation number of chlorine?
$H C l O_{4}, H O C l, C l F_{3}, H C l O_{3}$ and HCl.

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Solution

$H C l$ has the lowest oxidation number of chlorine.
The oxidation number of chlorine in $H C l$ is $- 1$
The oxidation number of chlorine in $H C l O_{4}, H O C l, C l F_{3}, H C l O_{3}$ is $+ 7$ , $+ 1$ , $+ 3$ and $+ 5$ respectively.

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Similar questions

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

H C l O_{4}

H C l O_{3}

H C l O_{4}

H C l O_{3}

H C l O_{4}

H C l O_{3}

(C l)

H C l O_{4}

H C l O_{3}

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