Which compound has planar structure?

X e F_{4}

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X e O F_{2}

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X e O_{2} F_{2}

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X e O_{4}

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Solution

The correct option is C $X e F_{4}$
In $X_{e} F_{4}$ molecule, central atom $X_{e}$ has $6$ electron pairs around it in which $4$ electron pairs are bonding pairs and $2$ electron pairs are lone pairs.
As $6$ electron pairs are three $X_{e} F_{4}$ structure should be octahedral but it square planar due to two lone pairs on it.
Because of two lone pairs repulsions increases and shape becomes square planar.

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