Which compound in each of the following pairs will react faster in $S N^{2}$ reaction with $O H^{-}$ ?
(i) $C H_{3} B r$ or $C H_{3} I$
(ii) $(C H_{3})_{3} C C l$ or $C H_{3} C l$

Open in App

Solution

(i) Since, iodide ion is better leaving group than bromide ion, methyl iodide will react faster than methyl bromide in $S N^{2}$ reaction with hydroxide ion.

(ii) Due to steric hinderance in tert butyl chloride, methyl chloride is more reactive than tert butyl chloride towards $S N^{2}$ reaction.

Suggest Corrections

Similar questions

Which compound in each of the following pairs will react faster in $S_{N} 2$ reaction with $¯ O H$ ?

$C H_{3} B r o r C H_{3} I$

$(C H_{3})_{3} C C l o r C H_{3} C l$

Which compound in each of the following pairs will react faster in $S N_{2}$ reaction with $¯ O H$ ?

S N^{2}

O H^{-} . (C H_{3})_{3} B r

C H_{3} B r

S_{N} 2

(C H_{3})_{3} C - B r

C H_{3} B r

S N_{2}

-

C H_{3} B r

C H_{3} I

S_{N} 2

C H_{3} B r

C H_{3} I

(C H_{3})_{3} C - C l

C H_{3} - C l

Join BYJU'S Learning Program