Question

Which of the following compound(s) is/are diamagnetic?

• A. ${\mathrm{Na}}_2{\mathrm{O}}_2$
• B. ${\mathrm{O}}_3$
• C. ${\mathrm{N}}_2\mathrm{O}$
• D. ${\mathrm{KO}}_2$

Answer 1

Answer: (A), (B), (C)

${\mathrm{N}}_2\mathrm{O}$

Explanation for the correct options:

Diamagnetic species: Diamagnetic species are those that have no unpaired electrons and are consequently not attracted to a magnetic field or if the number of the electron is even then the molecule is diamagnetic.

Options A, B and C are correct.

(A) ${\mathrm{Na}}_2{\mathrm{O}}_2:(2\times 11)+(2\times 8)=38$

It has even number of electrons so, it is diamagnetic in nature.

(B) ${\mathrm{O}}_3:(3\times 8)=24$

It has even number of electrons so, it is diamagnetic in nature.

(C)${\mathrm{N}}_2\mathrm{O}:(7\times 2)+(1\times 8)=22$

It also has even number of electrons so, it is diamagnetic in nature.

Explanation for the incorrect options:

(D) ${\mathrm{KO}}_2:(1\times 19+2\times 8)=35$

It has odd number of electrons so, it is paramagnetic in nature.

Therefore, correct answer is option (A), (B) and (C).