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Coordination Complexes

Which compoun...

Question

Which compound is formed when an excess of $K C N$ is added to an aqueous solution of copper sulphate?

A

$K_{3} [C u (C N)_{4}]$

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B

$K [C u (C N)_{2}]$

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C

$K_{2} [C u (C N)_{4}]$

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D

$C u (C N)_{2}$

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Solution

The correct option is A
$K_{3} [C u (C N)_{4}]$

$2 C u S O_{4} + 10 K C N ⟶ 2 K_{3} [C u (C N)_{4}] + 2 K_{2} S O_{4} + (C N)_{2}$

First $C u (C N)_{2}$ is formed which decomposes to form cyanogen $(C N)_{2}$ and $C u_{2} (C N)_{2}$ . $C u_{2} (C N)_{2}$ further combines with $K C N$ to form $K_{3} [C u (C N)_{4}]$ .

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Similar questions

Q. Select correct answer:

K F

H F

K H F_{2}

. The compound contains the species:
(a)

K^{+}, F^{-}

H^{+}

K^{+}, F

H F

K^{+}

[H F_{2}]^{-}

[K H F]^{+}

F^{-}

(II) Which compound is formed when excess of

K C N

is added to aqueous solution of copper sulphate?
(a)

C u (C N)_{2}

K_{2} [C u (C N)_{4}]

K [C u (C N)_{2}]

K_{3} [C u (C N)_{4}]

Q. When an excess of aqueous KCN solution is added to an aqueous solution of copper sulphate, the complex

[C u (C N)_{4}]^{2 -}

is formed. On passing

H_{2} S

gas through this solution no precipitate of CuS is formed because:

Q. Which compound is formed when excess of

K C N

is added to an aqueous solution of copper sulphate?

C u S O_{4}

decolourises on addition of KCN, the product is

Q. When aqueous

K C N

is added to a solution of

C u S O_{4}

, a white precipitate soluble in excess of

K C N

is formed. No precipitate is formed when

H_{2} S

gas is bubbled through the solution at this point because stable

[C u (C N)_{4}]^{3 -}

does not ionize to give

C u^{+}

.
If true enter 1, else enter 0.

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