Which compound is zero valent metal complex?

[C u (N H_{3})_{4}] S O_{4}

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[P t (N H_{3})_{2} C l_{2}]

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[N i (C O)_{4}]

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K_{3} [F e (C N)_{6}]

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Solution

The correct option is C $[N i (C O)_{4}]$

(a) $[C u (N H_{3})_{4}] S O_{4}$
Oxidation numbers of $C u$ :
$x + 4 \times 0 - 2 = 0$
$x - 2 = 0$
$x = + 2$

(b) Oxidation number of $P t$ in $[P t (N H_{3})_{2} C l_{2}]$
$x + 2 \times 0 + 2 \times - 1 = 0$
$x - 2 = 0$
$x = + 2$

(c) Oxidation number of $N i$ in $[N i (C O)_{4}]$
$x + 4 \times 0 = 0$
$x = 0$

(d) Oxidation number of $F e$ in $K_{3} [F e (C N)_{6}]$
$3 \times (+ 1) + x + 6 \times - 1 = 0$
$3 + x - 6 = 0$
$x = + 3$

$∴ [N i (C O)_{4}]$ is a zero-valent compound.
Hence, option $C$ is correct.

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Similar questions

IUPAC name for the complex $[C u (N H_{3})_{4}] S O_{4}$ is:

K_{4} [F e (C N)_{6}]

[C u (N H_{3})_{4}] S O_{4}

{F e (N H}_{4})_{2} {(S O}_{4})_{2} {(H}_{2} O)_{6}

K_{4} [{F e (C N)}_{6}]

K_{3} [F e (C N)_{6}]

18

[C u (N H_{3})_{4}]^{2 +}, [C u (e n)_{3}]^{2 +}, [C u (C N)_{4}]^{3 -}

[F e (C N)_{6}]^{4 -}, [F e (C N)_{6}]^{3 -}, F e (C O)_{6}

[N i (N H_{3})_{6}]^{2 +}, [N i (C N)_{4}]^{2 -}, [N i (C O)_{4}]

[C r (N H_{3})_{6}]^{3 +}, [C r (C O)_{6}]

[C o (N H_{3})_{6}]^{3 +}, [C o C l_{4}]^{2 -}

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