Which compound will liberate $C O_{2}$ from $N a H C O_{3}$ solution :

C H_{3} C O N H_{2}

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C H_{3} N H_{2}

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{(C H_{3})}_{4} N^{+} O H^{-}

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C H_{3} N^{+} H_{3} C l^{-}

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Solution

The correct option is D $C H_{3} N^{+} H_{3} C l^{-}$
$C H_{3} N^{+} H_{3} C l^{-}$ will react with $N a H C O_{3}$ to liberate $C O_{2}$ .
$C H_{3} N^{+} H_{3} C l^{-} + N a H C O_{3} \to C H_{3} N H_{2} + N a C l + H_{2} O + C O_{2}$

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Similar questions

C O_{2}

N a H C O_{3}

How many of the following compounds liberate $C O_{2}$ with $N a H C O_{3}$ ?

C O_{2}

N a H C O_{3}

N a H C O_{3}

C O_{2}

C O_{2}

N a H C O_{3}

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