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Question

Which congruence criterion do you use in the following?
Given: EB$$=$$BD, AE$$=$$CB, $$\angle$$A$$=\angle$$C$$=90^o$$. So $$\Delta$$ABE$$\equiv \Delta$$CDB.
1646082_50e5815d298b41eeb44c660ea2da2c16.png


Solution

By RHS congruence criterion, 
since it is given that
 EB$$=$$BD, AE$$=$$CB, $$\angle$$A$$=\angle$$C$$=90^o$$
Hypotenuse and one side of a right angled triangle
 are respectively equal to the hypotenuse and one side
 of another right angled triangle.
Therefore,
 $$\Delta$$ABE$$\cong\Delta$$CDB.

Mathematics
NCERT
Standard VII

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