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Question

Which congruency rule(s) is/are used to prove the construction of a perpendicular bisector?

A
SAS
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B
SSS
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C
RHS
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D
ASS
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Solution

The correct options are
A SAS
B SSS

In PAQ and PBQ
AP = BP ; AQ = BQ (Equal radii)
PQ = PQ (Common side)
PAQ PBQ [SSS rule]
So APQ=BPQ.... CPCT

Now In APO and BPO
AP = BP (Equal radii)
APO=BPO (Proved above)
OP = OP (Common)
APO BPO [SAS rule]

So OA = OB and
AOP=BOP [CPCT]
But, AOP+BOP = 180° [Linear pair]
2AOP= 180°
AOP= 90°

Thus we can see SSS and SAS congruency rules are used in the above proof.

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