The correct option is C Friday
2nd Oct 1942 = 1941 years + Period from 01/01/1942 to 02/10/1942
1600 years have 0 odd days.
300 years have 1 odd days.
Now, 41 years comprise of 10 leap years and 31 ordinary years.
So, the number of odd days in 41 years =10 2 + 31 = 51 = 7 weeks and 2 odd days.
In 1942, till 2nd Oct, the number of odd days is calculated as follows:
Month Jan Feb Mar Apr May Jun July Aug Sept Oct
Days 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 2 = 275 days or 39 weeks and 2 odd days
So, total number of odd days = 0 + 1 + 2 + 2 = 5 odd days.
Hence, the day on 2nd Oct 1942 is Friday (Counting 5 days from Monday).