Which displacement reaction will not occur among the following reactions?

Z n_{(s)} + C u S O_{4 (a q)}

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F e_{(s)} + C u S O_{4 (a q)}

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C u_{(s)} + F e S O_{4 (a q)}

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M g_{(s)} + C u S O_{4 (a q)}

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Solution

The correct option is C $C u_{(s)} + F e S O_{4 (a q)}$
The displacement reaction $C u_{(s)} + F e S O_{4 (a q)} \to F e_{(s)} + C u S O_{4 (a q)}$ will not occur.
The displacement reaction $F e_{(s)} + C u S O_{4 (a q)} \to C u_{(s)} + F e S O_{4 (a q)}$ will occur.
This is because iron is placed below copper in the electrochemical series.
Copper is a weaker reducing agent than iron.

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Similar questions

Which of the following reactions will not occur ? Why not?
(a) $M g S O_{4} (a q) + C u (s) ⟶ C u S O_{4} (a q) + M g (s)$
(b) $C u S O_{4} (a q) + F e (s) ⟶ F e S O_{4} (a q) + C u (s)$
(c) $M g S O_{4} (a q) + F e (s) ⟶ F e S O_{4} (a q) + M g (s)$

Q. State, giving reasons, which of the following reactions will occur and which will not:
(a) MgSO₄ (aq) + Cu(s) → CuSO₄ (aq) + Mg(s)
(b) CuSO₄ (aq) + Fe (s) → FeSO₄(aq) + Cu(s)
(c) MgSO₄ (aq) + Fe (s) → FeSO₄ (aq) + Mg(s)

Q. Which of the following reactions will not occur? Why not?
(a)

{MgSO}_{4} (aq) + Cu (s) \underset{}{\to} {CuSO}_{4} (aq) + Mg (s)

(b)

{CuSO}_{4} (aq) + Fe (s) \underset{}{\to} {FeSO}_{4} (aq) + Cu (s)

(c)

{MgSO}_{4} (aq) + Fe (s) \underset{}{\to} {FeSO}_{4} (aq) + Mg (s)

Q. State which of the following chemical reactions will take place or not, giving suitable reason for each:

(a) Z n_{(s)} + C u S o_{4 (a q)} \to Z n S O_{4 (a q)} + C u_{(s)}

(b) F e_{(s)} + Z n S O_{4 (a q)} \to F e S O_{4 (a q)} + Z n_{(s)}

(c) Z n_{(s)} + F e S O_{4 (a q)} \to Z n S O_{4 (a q)} + F e_{(s)}

C u S O_{4} (a q) + F e (s) \to F e S O_{4} (a q) + C u (s) F e S O_{4} (a q) + Z n (s) \to Z n S O_{4} (a q) + F e (s)

Choose the correct answer, among the following statements.

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