Question

Which electron,orbitals are designated by
(i) n= 2, l=1, m= 0;
(ii)n= 3, l= 2, m= 0;
(iii)n = 4, l = 2, m = 1 and
(iv) n = 5, I= 3, m =3 respectively ?

• A. 2p, 3d, 4d and 5f, respectively
• B. 2p, 3d, 4d and 5d, respectively
• C. 2p, 3d, 4f and 5f, respectively
• D. 2p, 3p, 4d and 5f, respectively

Answer 1

The correct option is A 2p, 3d, 4d and 5f, respectively

For $\left(i\right)n=2,l=1,m=.0$; the orbital occupied by electron is 2p.

For$\left(ii\right)n=3,l=2,m=0$ ;the orbital occupied by electron is 3d.

For$\left(iii\right)n=4,l=2,m=1$; the orbital occupied by electron is 4d.

For $\left(iv\right)n=5,l=3,m=3$; the orbital occupied by electron is 5f.