You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxides of Nitrogen

Which equatio...

Question

Which equation in gaseous phase would be unaffected by an increase in pressure?

N_{2} O_{4} ⇌ {2 N O}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N_{2} + O_{2} ⇌ 2 N O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N_{2} + {3 H}_{2} ⇌ 2 {N H}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C O + \frac{1}{2} O_{2} ⇌ {C O}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $N_{2} + O_{2} ⇌ 2 N O$
According to Le chatelier principle; If the number of moles of gaseous reactants and products, the pressure will have no effect on the equilibrium.
$N_{2} + O_{2} ⇌ 2 N O$
Number of moles of reactants = Number of moles of product
So, the correct answer is option B.

Suggest Corrections

Similar questions

N_{2} + 3 H_{2} \to 2 N H_{3} - K_{1}

N_{2} + O_{2} \to 2 N O - K_{2}

H_{2} + 1 / 2 O_{2} \to H_{2} O - K_{3}

3 H_{2} + 5 / 2 O_{2} \to 2 N O + 3 H_{2} O

K_{1}, K_{2}, K_{3}

N_{2} + 3 H_{2} ⇌ 2 N H_{3}

K_{1}

N_{2} + O_{2} ⇌ 2 N O

K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O

K_{3}

2 N H_{3} + \frac{5}{2} O_{2} ⇌ 2 N O + 3 H_{2} O

K_{1}, K_{2}

K_{3}

N_{2} + 3 H_{2} ⇌ 2 N H_{3}

K_{1}

N_{2} + O_{2} ⇌ 2 N O

K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O

K_{3}

2 N H_{3} + \frac{5}{2} O_{2} ⇌ 2 N O + 3 H_{2} O

K_{1}, K_{2}

K_{3}

N_{2} + 3 H_{2} ⇌ 2 N H_{3}, K_{1}

N_{2} + O_{2} ⇌ 2 N O, K_{2}

H_{2} + \frac{1}{2} O_{2} ⇌ H_{2} O, K_{3}

K_{1}, K_{2}

K_{3}

2 N H_{3} + \frac{5}{2} O_{2} ⇌ 2 N O + 3 H_{2} O

N_{2} + 3 H_{2} ⇌ 2 N H_{3}; K_{1}

N_{2} + O_{2} ⇌ 2 N O; K_{2}

H_{2} + \frac{1}{2} O_{2} \to H_{2} O; K_{3}

(K)

2 N H_{3} + \frac{5}{2} O_{2} K ⇌ 2 N O + 3 H_{2} O

Join BYJU'S Learning Program