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Special Integrals - 1

Which gives p...

Question

Which gives ppt with $K_{2} {C r O}_{4}$ ?

A

{H g}_{2}^{2 +}, {P b}^{2 +}, {A g}^{+}, {B a}^{2 +}

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B

{P b}^{2 +}, {A g}^{+}, {B a}^{2 +}

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C

{A g}^{+}, {B a}^{2 +}

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D

{P b}^{2 +}, {B a}^{2 +}

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Solution

The correct option is A ${H g}_{2}^{2 +}, {P b}^{2 +}, {A g}^{+}, {B a}^{2 +}$
${H g}_{2}^{2 +}, {P b}^{2 +}, {A g}^{+}, {B a}^{2 +}$ gives ppt with $K_{2} {C r O}_{4}$

For example, Silver ions react with potassium chromate to form black red precipitate of $A g_{2} C r O_{4}$ .

${P b}^{2 +} o r {B a}^{2 +}$ react with $K_{2} {C r O}_{4}$ to form yellow ppt of lead chromate or barium chromate respectively.

${P b}^{2 +} + K_{2} {C r O}_{4} \to P b {C r O}_{4} + 2 K^{+}$

${B a}^{2 +} + K_{2} {C r O}_{4} \to B a {C r O}_{4} + 2 K^{+}$

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