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Question

Which greatest number will divide 3026 and 5053 leaving remainders 11 and 13 respectively?

A
15
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B
30
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C
45
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D
60
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Solution

The correct option is C 45
To find required number we have to find HCF of (302611) and (505313)
Now, HCF of 3015 and 5040
To find HCF, we break the given numbers in their prime Factors.
3015=3×3×5×67
5040=2×2×2×2×3×3×5×7
We take common multiples in these two given numbers to get required HCF.
And Common multiples are: 3×3×5
So, Required HCF = 45.
The required number is 45.

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