Which has a maximum number of atoms?

24 grams of C-12

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27 grams of Al-27

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56 grams of Fe-56

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108 grams of Ag-108

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Solution

The correct option is A
24 grams of C-12

$N u m b e r o f m o l e s = \frac{w e i g h t}{m o l e c u l a r w e i g h t}$

24 grams of C-12

$⟹ \frac{24}{12} = 2 M o l e s$

27 grams of Al-27

$⟹ \frac{27}{27} = 1 M o l e$

56 grams of Fe-56

$⟹ \frac{56}{56} = 1 M o l e$

108 grams of Ag-108

$⟹ \frac{108}{108} = 1 M o l e$

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Similar questions

C, F e, A l, A g

12, 56, 27, 108

100

100

N A = 23 u, F e = 56 u

Which has more number of atoms, 100 grams of sodium or 100 grams of iron (given, atomic mass of Na = 23 u, Fe = 56 u)? [3 MARKS]

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