Question

Which has a maximum number of molecules?

• A. 1 g of ${\mathrm{CO}}_2$
• B. 1 g of ${\mathrm{N}}_2$
• C. 1 g of ${\mathrm{CH}}_4$.
• D. 1 g of ${\mathrm{H}}_2$

Answer 1

The correct option is C

1 g of ${\mathrm{CH}}_4$.

(a)1g of ${\mathrm{CO}}_2$

number of moles =$\frac{mass}{atomicmass}$

Number of moles of 1g of ${\mathrm{CO}}_2$=$\frac{1}{44}$

Number of molecules =$\frac{1}{44}$$\times 6.023\times {10}^{23}$

= 1.368$\times {10}^{22}moleculesofC{O}_2$

(b) 1 g of ${\mathrm{N}}_2$

Number of molecules =$\frac{1}{28}$$\times 6.023\times {10}^{23}$

=2.151$\times {10}^{22}$molecules of ${\mathrm{N}}_2$

( c)1 g of ${\mathrm{H}}_2$

Number of molecules =$\frac{6.023\times {10}^{23}\times 1}{2}$

=$3.011\times {10}^{23}$molecules of hydrogen ${\mathrm{H}}_2$

(d) 1 g of ${\mathrm{CH}}_4$=$\frac{6.023\times {10}^{23}\times 1}{16}$

=3.764$\times {10}^{22}$ molecules of ${\mathrm{CH}}_4$

Hence the correct option is (d)-1 g of ${\mathrm{CH}}_4$