The correct option is D O+
N(7) and O+(8−1=7)=1s22s22p1x2p1y2p1zMaximum multiplicity most stable
P=1s2,2s22p2x,2p1y,2p1z
Ionisation potential is dependent on the value of Z.
Z of O+(8)>Z of N(7)
Thus, ionisation potential of O+>N
Na with one valence electron has least ionisation potential.