Question

Which has maximum number of molecules?

• A. $7g{N}_2$
• B. $2g{H}_2$
• C. $16g{NO}_2$
• D. $16g{O}_2$

Answer 1

Answer: (B)

$2g{H}_2$

Answer:-

No. of moles = $\frac{\text{Weight}\left(W\right)}{\text{Molecular weight}\left(M\right)}$

Therefore,

(a) No. of moles =$\frac{7}{28}$ = 0.25 moles

(b) No. of moles =$\frac{2}{2}$ = 1 mole

(c) No. of moles =$\frac{16}{46}$ = 0.347 moles

(d) No. of moles =$\frac{16}{32}$ = 0.5 moles

Since $H_2$ has maximum no. of moles, hence it has maximum no. of molecules.