Which has maximum solubility $A B, A B_{2}, A B_{3}, A B_{4}$ if $K_{s p}$ for all the salts are $10^{- 10}$ ?

A B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A B_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A B_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A B_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $A B_{4}$
$A B ⇌ A^{+} + B^{-}$
$K_{s p} = [A^{+}] [B^{-}] = (S) (S) = S^{2}$
$A B_{2} ⇌ A^{+} + 2 B^{-}$
$K_{s p} = [A^{+}] [B^{-}]^{2} = (S) (2 S)^{2} = 4 S^{3}$
$A B_{3} ⇌ A^{+} + 3 B^{-}$
$K_{s p} = [A^{+}] [B^{-}]^{3} = (S) (3 S)^{3} = 27 S^{4}$
$A B ⇌ A^{+} + 4 B^{-}$
$K_{s p} = [A^{+}] [B^{-}]^{4} = (S) (4 S)^{4} = 256 S^{5}$
So $A B_{4}$ has maximum solubility.

Suggest Corrections

Similar questions

(K_{s p})

K_{s p}

A B, A B_{2}

A_{3} B

4.0 \times 10^{- 8}, 3.2 \times 10^{- 14}

2.7 \times 10^{- 15}

^{- 1}

S. No.	Formula Type	Solubility Product
1. 2. 3.	$A B$ $A_{2} B$ $A B_{3}$	$4.0 \times 10^{- 20}$ $3.2 \times 10^{- 11}$ $2.7 \times 10^{- 31}$

A B_{2}

4 \times 10^{- 12}

Join BYJU'S Learning Program