Question

Which has more atoms:$100$g of $N_2$or $100$g of $N{H}_3$?

Answer 1

$\left(i\right)100g{N}_2$ contains $=\frac{100}{28}$ moles
Number of molecules$=\frac{100}{28}\times 6.022\times {10}^{23}$
Number of atoms$=\frac{100}{28}\times 6.022\times {10}^{23}\times 2=43.01\times {10}^{23}$
(ii) $100gN{H}_3=\frac{100}{17}$
$=\frac{100}{17}\times 6.022\times {10}^{23}$
$=\frac{100}{17}\times 6.022\times {10}^{23}\times 4$
$=141.69\times {10}^{23}$
$\therefore N{H}_3$would have more atoms