Question

Which has more no.of atom 100 g of Na or 100 g of Fe ?

Answer 1

$n_{Na}=\frac{100}{23}$ , No. of atoms = $\left(\frac{100}{23}\right)N_A$
$n_{Fe}=\frac{100}{56},$ no. of atoms = $\left(\frac{100}{56}\right)N_A$
$\frac{100}{23}{N}_A>\frac{100}{56}{N}_A$
No. of atoms of Na > no of atom of Fe