Question

Question 37
Which has more number of atoms?
100g on $N_2$ or 100 g of $N{H}_3$

Answer 1

Molar mass of $N_2=2\times 14=28g$
$\because$ 28 g of $N_2$ has number of molecules $=6.022\times {10}^{23}$
$\because$ 100 g of $N_2$ has number of molecules $=\frac{6.022\times {10}^{23}\times 100}{28}=2.1\times {10}^{24}$
Atoms in 100 g of $N_2=2.1\times {10}^{24}\times 2$
$=4.2\times {10}^{24}atoms$
Similarly, molar mass of $N{H}_3=14+3\times 1=17g$
$\because$ 17 g $N{H}_3$ has number of molecules $=6.022\times {10}^{23}$
$\therefore$ 100 g $N{H}_3$ has number of molecules $=\frac{6.022\times {10}^{23}\times 100}{17}=3.54\times {10}^{24}$
Atoms in 100 g of $N{H}_3=3.54\times {10}^{24}\times 4=1.416\times {10}^{25}$
Thus, 100 g of $N{H}_3$ has more number of atom.