Question

Which has the maximum numbers of atoms?
(Given: Molar mass of C, Fe, Al, Ag = 12, 56, 27, 108 respectively).

• A. 24 g of C
• B. 56 g of Fe
• C. 27 g of Al
• D. 108 g of Ag

Answer 1

The correct option is A 24 g of C

$\text{Number of atoms}=n\times N_A=\frac{\text{mass}}{\text{molar mass}}\times N_A$

$\left(a\right)\frac{24}{12}\times N_A=2\times N_A$
$\left(b\right)\frac{56}{56}\times N_A=1\times N_A$
$\left(c\right)\frac{27}{27}\times N_A=1\times N_A$
$\left(d\right)\frac{108}{108}\times N_A=1\times N_A$

Hence. (a) has the maximum number of atoms.