Question

Which has the maximum numbers of atoms?
(Given: Molar mass of $C,Fe,Al,Ag$ are $12,56,27,108$ respectively).

• A. $24\text{g}$ of $C$
• B. $56\text{g}$ of $Fe$
• C. $27\text{g}$ of $Al$
• D. $108\text{g}$ of $Ag$

Answer 1

The correct option is A $24\text{g}$ of $C$

$\text{Number of atoms}=n\times N_A=\frac{\text{mass}}{\text{molar mass}}\times N_A$

$\left(a\right)\frac{24}{12}\times N_A=2\times N_A$
$\left(b\right)\frac{56}{56}\times N_A=1\times N_A$
$\left(c\right)\frac{27}{27}\times N_A=1\times N_A$
$\left(d\right)\frac{108}{108}\times N_A=1\times N_A$

Hence (a) has the maximum number of atoms.